SAN DIEGO — A new study by the price-monitoring website PriceListo lists America's Finest City as the most expensive city in the U.S. to go on a night out.
Charlotte, North Carolina, followed with a night out costing, on average, $224.75, and Austin, Texas, with an average of $221.23.
The study collected the cost of living data from each U.S. city with a population of 500,000. The study compared the average price of a cocktail, cab fare for a three-mile journey, a bottle of wine, and a pint of beer. And then added together the prices for an overall cost.
The study also analyzed data from the hotel site "Vio" to discover the median prices for each city's one-night stay in a budget hotel.
The study finds that a pint of beer in San Diego costs $8.00, the second highest in the nation. A one-night hotel stay in America's Finest City is the third highest, costing 167.28 dollars.
Top 10 most expensive US cities for a night out:
- San Diego - $225.27
- Charlotte - $224.75
- Austin - $221.23
- Memphis - $216.25
- Columbus - $212.47
- Boston - $211.16
- Seattle - $210.61
- Washington, DC - $210.39
- Houston - $209.54
- Tucson - $203.39
According to the study, the cheapest pint of beer and cocktails was in San Antonio, Texas. But the most affordable city in the U.S. for a night out was Las Vegas.
Top 10 most affordable US cities for a night out:
- Las Vegas - $120.76
- San Antonio - $134.56
- Oklahoma City - $136.98
- San Francisco - $142.94
- Fresno - $145.55
- Albuquerque - $157.47
- Jacksonville - $162.42
- Philadelphia - $168.74
- Fort Worth - $172.14
- Chicago - $173.81
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